Add new simplification rule

This adds the rule “(not F or G) === (F -> G)” to the simplification
rule tableau.
This commit is contained in:
Patrick Lühne 2018-04-09 23:46:19 +02:00
parent 6f7b021712
commit 40ddee8444
Signed by: patrick
GPG Key ID: 05F3611E97A70ABF
4 changed files with 41 additions and 4 deletions

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@ -430,6 +430,42 @@ struct SimplificationRuleDeMorganForConjunctions
////////////////////////////////////////////////////////////////////////////////////////////////////
struct SimplificationRuleImplicationFromDisjunction
{
static constexpr const auto Description = "(not F or G) === (F -> G)";
static SimplificationResult apply(ast::Formula &formula)
{
if (!formula.is<ast::Or>())
return SimplificationResult::Unchanged;
auto &or_ = formula.get<ast::Or>();
if (or_.arguments.size() != 2)
return SimplificationResult::Unchanged;
const auto leftIsNot = or_.arguments[0].is<ast::Not>();
const auto rightIsNot = or_.arguments[1].is<ast::Not>();
if (leftIsNot == rightIsNot)
return SimplificationResult::Unchanged;
auto &negativeSide = leftIsNot ? or_.arguments[0] : or_.arguments[1];
auto &positiveSide = leftIsNot ? or_.arguments[1] : or_.arguments[0];
assert(negativeSide.is<ast::Not>());
assert(!positiveSide.is<ast::Not>());
auto &negativeSideArgument = negativeSide.get<ast::Not>().argument;
formula = ast::Formula::make<ast::Implies>(std::move(negativeSideArgument), std::move(positiveSide));
return SimplificationResult::Simplified;
}
};
////////////////////////////////////////////////////////////////////////////////////////////////////
const auto simplifyWithDefaultRules =
simplify
<
@ -442,7 +478,8 @@ const auto simplifyWithDefaultRules =
SimplificationRuleExistsWithoutQuantifiedVariables,
SimplificationRuleInWithPrimitiveArguments,
SimplificationRuleSubsumptionInBiconditionals,
SimplificationRuleDeMorganForConjunctions
SimplificationRuleDeMorganForConjunctions,
SimplificationRuleImplicationFromDisjunction
>;
////////////////////////////////////////////////////////////////////////////////////////////////////

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@ -153,7 +153,7 @@ TEST_CASE("[completion] Rules are completed", "[completion]")
CHECK(output.str() ==
"forall V1 (covered(V1) <-> exists U1 in(V1, U1))\n"
"forall V2, V3 (in(V2, V3) -> (V2 in 1..n and V3 in 1..r))\n"
"forall U2 (not U2 in 1..n or covered(U2))\n"
"forall U2 (U2 in 1..n -> covered(U2))\n"
"forall U3, U4, U5 (not in(U3, U4) or not in(U5, U4) or not exists X1 (X1 in (U3 + U5) and in(X1, U4)))\n");
}

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@ -168,7 +168,7 @@ TEST_CASE("[hidden predicate elimination] Hidden predicates are correctly elimin
CHECK(output.str() ==
"(s -> not #false)\n"
"(t -> not #false)\n"
"(not s or t)\n"
"(s -> t)\n"
"(#false or #false or not #false)\n");
}

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@ -56,7 +56,7 @@ TEST_CASE("[placeholders] Programs with placeholders are correctly completed", "
CHECK(output.str() ==
"forall V1, V2 (color(V1, V2) -> (vertex(V1) and color(V2)))\n"
"forall U1 (not vertex(U1) or exists U2 color(U1, U2))\n"
"forall U1 (vertex(U1) -> exists U2 color(U1, U2))\n"
"forall U3, U4, U5 (not color(U3, U4) or not color(U5, U4) or not edge(U3, U5))\n");
}
}